Ex 5 2 18 The Sum Of 4th And 8th Terms Of An Ap Is 24 The sum of 4 t h and 8 t h form of an a p is 24 and the sum of its 6 t h and 10 t h terms is 44. find the sum of first 10 t h t e r m s of a p . view solution. If the ratio of the sum of the first n terms of two a.ps is (7n 1) : (4n 27), then find the ratio of their 9 th terms. find the sum of 28 terms of an a.p. whose n th term is 8n – 5. if 4 times the 4 th term of an ap is equal to 18 times its 18 th term then find its 22 nd term. find the sum of all natural numbers between 200 and 400 which.
Ex 5 2 18 The Sum Of 4th And 8th Terms Of An Ap Is 24 The sum of the 4 th and 8 th terms of an ap is 24 and the sum of the 6 th and 10 th terms is 44. find the first three terms of the ap. solution: the formula for n th term of an ap is aₙ = a (n 1) d. here, aₙ is the n th term, a is the first term, d is the common difference and n is the number of terms. given, a₄ a₈ = 24 (a 3d. The sum of the 4 t h and 8 t h terms of an ap is 24 and the sum of the 6 t h and 10 t h terms is 44. find the first three terms of the ap. find the first three terms of the ap. q. It is given that, sum of 4 th & 8 th terms of ap is 24 which implies, a 4 98 = 24 putting values we get: ⇒ a 3 d a 7 d = 24 ⇒ 2 a 10 d = 24 now we will divide by 2 both sides, we get: ⇒ a 5 d = 12 . . . . 1 it is also given that the sum of 6 th and 10 th term of ap is 44 ⇒ a 6 a 10 = 44. Transcript. ex 5.2, 18 the sum of 4th and 8th terms of an a.p. is 24 and the sum of the 6th and 10th terms is 44. find the first three terms of the a.p. we know that an = a (n – 1) d so, a4 = a (4 – 1) d a4 = a 3d also, a8 = a (8 – 1)d a8 = a 7d similarly, a6 = a (6 – 1)d a6 = a 5d and a10 = a (10 – 1)d a10 = a 9d.
Comments are closed.