Question 6 Find General Solution Of Cos 3x Cos X Cos 2x

Question 6 Find General Solution Of Cos 3x Cos X Cos 2x 0 Transcript. question 6 find the general solution of the equation cos 3x cos x – cos 2x = 0 cos 3x cos x – cos 2x = 0 (cos 3x cos x) – cos 2x = 0 2 cos. Ncert solutions class 11 maths chapter 3 exercise 3.4 question 6. find the general solution for each of the following equations: cos 3x cos x cos 2x = 0. summary: the general solution of the equation cos 3x cos x cos 2x = 0 is x = [(2n 1)π 4] or x = 2nπ ± π 3, where n∈z.

Question 6 Find General Solution Of Cos 3x Cos X Cos 2x 0 The equation \[3 \cos x 4 \sin x = 6\] has . solution. if \[\sqrt{3} \cos x \sin x = \sqrt{2}\] , then general value of x is. the number of values of x in the interval [0, 5 π] satisfying the equation \[3 \sin^2 x 7 \sin x 2 = 0\] is. find the principal solution and general solution of the following: cot θ = `sqrt(3)` find the. Solve equation general solution for:cosx cos3x−2cos2x = 0. view solution. click here:point up 2:to get an answer to your question :writing hand:find the general solution of the equation cos 3x cos x cos 2x. 3x = nπ or 2x = 2mπ ± π 3. x = nπ 3 or x = mπ ± π 6. ∴ the general solution is. x = nπ 3 or mπ ± π 6, where m, n ϵ z. (iv) given as cos x cos 2x cos 3x = 1 4. now let us simplify, cos x cos 2x cos 3x = 1 4. 4 cos x cos 2x cos 3x – 1 = 0. on using the formula, 2 cos a cos b = cos (a b) cos (a – b) 2(2cos x cos 3x) cos 2x. Cos(3x) cos(x) = 0 cos (3 x) cos (x) = 0. when i tried calculating it by evaluating x x, x = 2nπ π 4 x = 2 n π π 4, x = 2nπ − π 4 x = 2 n π − π 4, or x = 2nπ π 2 x = 2 n π π 2 was the solution i reached. unfortunately, it was apparently wrong. is there another way to solve this problem? trigonometry.