Given That E_cu2 Cu00 337 And E_cu Cu2

Given I Cu2 2e в Cu Eв 0 337 V Ii Cu2 в в Cut Eв 0 Given (i) cu2 2e– cu, eo = 0.337 v (ii) cu2 e– cu , eo = 0.153 v electrode potential, eo for the reaction, cu e– cu, will be (1) 0.38 v (2) 0.52 v (3) 0.90 v (4) 0.30 v view solution q 2. Given : (i) cu2 2e → cu, e° = 0.337 v (ii) cu2 e → cu , e° = 0.153 v electrode potential, e° v (b) 0.30 v (c) 0.38 v (d) 0.52 v.

Given I Cu2 2e Cu Eв 0 337 V Ii Cu2 E Cut Eв 0 153 V Given that e°(cu2 cu) = 0.337 v and e° (cu cu2 ) = – 0.153 v. then calculate e°(cu cu). [in volt]. 📲pw app link bit.ly ytai. Electrode potential, e ∘ for the reaction, c u e − → c u, will be q. given that the standard potential ( e ∘ ) of c u 2 c u and c u c u are 0.340 v and 0.522 v respectively. From the given, (1) c u 2 2 e → c u e ° = 0. 337 v Δ g = n f e ° ⇒ Δ g = 2 * f * 0. 3370 [i] (2) c u 2 e → c u e ° = 0. 153 v Δ g = n f e ° ⇒ Δ g = 1 * f * 0. 153 [i i] adding the equations (i) and (ii), c u e → c u Δ g ° = 0. 521 f Δ g ° = n f e ° ⇒ 0. 521 f = n f e ° ⇒ e ° = 0. 52 v. explanation of. Given i) cu2 2 e → cu, e° = 0.337 ii) cu2 e → cu , e° = 0.153 v electrode potential, e for the v b) 0.30 v c) 0.38 v d) 0.52 v.

Given I Cu2 2e в Cu Eв 0 337 V Ii Cu2 в в Cut Eв 0 From the given, (1) c u 2 2 e → c u e ° = 0. 337 v Δ g = n f e ° ⇒ Δ g = 2 * f * 0. 3370 [i] (2) c u 2 e → c u e ° = 0. 153 v Δ g = n f e ° ⇒ Δ g = 1 * f * 0. 153 [i i] adding the equations (i) and (ii), c u e → c u Δ g ° = 0. 521 f Δ g ° = n f e ° ⇒ 0. 521 f = n f e ° ⇒ e ° = 0. 52 v. explanation of. Given i) cu2 2 e → cu, e° = 0.337 ii) cu2 e → cu , e° = 0.153 v electrode potential, e for the v b) 0.30 v c) 0.38 v d) 0.52 v. (i) cu 2 2e → cu, e 0 = 0.337v (ii) cu 2 e → cu , e 0 = 0.153v electrode potential, e 0 for the reaction,cu e → cu, will be unlock the full solution & master the concept. get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept. Use the standard reduction potentials given below: cu2 2e ? cu e o red = 0.337 v. mg2 2e ? mg e o red = 2.37 v. what is the calculated value of the cell potential at 298 k for an electrochemical cell with the following reaction, when the cu2 concentration is 2.51 x 10 4 m and the mg2 concentration is 1.05 m?.