Chemistry Sec 1 Writing Chemical Formulas Part 2 2 Unit 2

Chemistry Sec 1 Writing Chemical Formulas Part 2 2 Unit 2 Chemistrysecondary 1 first termunit 2: quantitative chemistrychapter 1: the mole and the chemical equation.the prelude lesson : writing the chemical formul. Methane and oxygen react to yield carbon dioxide and water in a 1:2:1:2 ratio. this ratio is satisfied if the numbers of these molecules are, respectively, 1 2 1 2, or 2 4 2 4, or 3 6 3 6, and so on . likewise, these coefficients may be interpreted with regard to any amount (number) unit, and so this equation may be correctly read in many ways.

Chemistry Sec 1 Writing The Chemical Formulas 2 Unit Example 4.2.2: combustion of glucose. the balanced chemical equation for the combustion of glucose in the laboratory (or in the brain) is as follows: c 6h 12o 6(s) 6o 2(g) → 6co 2(g) 6h 2o(l) construct a table showing how to interpret the information in this equation in terms of. a single molecule of glucose. 2 × 2 = 4. (1 × 2) (2 × 1) = 4. 4 = 4, yes. a balanced chemical equation often may be derived from a qualitative description of some chemical reaction by a fairly simple approach known as balancing by inspection. consider as an example the decomposition of water to yield molecular hydrogen and oxygen. this process is represented. O. 2 × 1 = 2. 1 × 2 = 2. 2 = 2, yes. these coefficients yield equal numbers of both h and o atoms on the reactant and product sides, and the balanced equation is, therefore: 2h 2o → 2h 2 o 2. video 5.1.3: a review of balancing chemical equations, with extra practice problems. O. 2 × 1 = 2. 1 × 2 = 2. 2 = 2, yes. the h atom balance was upset by this change, but it is easily reestablished by changing the coefficient for the h 2 product to 2. 2 h2o 2 h2 o2 (balanced) 2 h 2 o 2 h 2 o 2 (balanced) tally chart for decomposition of water to yield hydrogen and oxygen #3. element.

Writing Chemical Formulas Level 2 O. 2 × 1 = 2. 1 × 2 = 2. 2 = 2, yes. these coefficients yield equal numbers of both h and o atoms on the reactant and product sides, and the balanced equation is, therefore: 2h 2o → 2h 2 o 2. video 5.1.3: a review of balancing chemical equations, with extra practice problems. O. 2 × 1 = 2. 1 × 2 = 2. 2 = 2, yes. the h atom balance was upset by this change, but it is easily reestablished by changing the coefficient for the h 2 product to 2. 2 h2o 2 h2 o2 (balanced) 2 h 2 o 2 h 2 o 2 (balanced) tally chart for decomposition of water to yield hydrogen and oxygen #3. element. To balance the number of o atoms, write a 3 in from of the o2 and a 2 in front of the fe2o3: fe 3 o2 → 2 fe2o3. the equation, above, now has 6 atoms of o on each side, but the fe atoms are not balanced. since there is 1 atom of fe on the left and 4 atoms of fe on the right, the fe atoms can be balanced by writing a 4 in front of the fe: 4. Methane and oxygen react to yield carbon dioxide and water in a 1:2:1:2 ratio. this ratio is satisfied if the numbers of these molecules are, respectively, 1 2 1 2, or 2 4 2 4, or 3 6 3 6, and so on . likewise, these coefficients may be interpreted with regard to any amount (number) unit, and so this equation may be correctly read in many ways.